You can plot stuff in Google earth using kml - not too hard to generate.
QO-100 DXCC and User Statistic
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I have generated a nice map using the Azimuthal map generator at https://ns6t.net/azimuth/azimuth.html
Center the map at 0°N 26°E and set the radius to 9000km, and if you print the map as a poster on 6-8 A4 sheets you have a nice wall deco
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If you want to see the 5 and 10 deg rings, go to https://www.satbeams.com/footprints?beam=9796
The point is that I wish to zoom the map in !! Like I said in my original post, I don't want the zooming-in to degrade the view !! I want it to add information !
Your URL achieves that, thankyou!
I also had a reply from Peter, 2M0SQL, who suggested https://www.n2yo.com/?s=43700 selecting "Draw Footprint" and then "Large Map"
Thanks to all!
73's David
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You can plot stuff in Google earth using kml - not too hard to generate.
Easy when you know how! Thanks for that... (I don't even know what KML is... (yet!))
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I have generated a nice map using the Azimuthal map generator at https://ns6t.net/azimuth/azimuth.html
Center the map at 0°N 26°E and set the radius to 9000km, and if you print the map as a poster on 6-8 A4 sheets you have a nice wall deco
Thanks... It was all going so well until I got this !!
Internal Server Error
The server encountered an internal error or misconfiguration and was unable to complete your request.
Please contact the server administrator at webmaster@localhost to inform them of the time this error occurred, and the actions you performed just before this error.
More information about this error may be available in the server error log.
Apache/2.4.38 (Debian) Server at ns6t.net Port 443
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Please enter simply
0, 26
for location. Then it works.
" The second way is to use a latitude/longitude pair as two real numbers
separated by a comma. A positive number for latitude means north, and
a negative value means south. For longitude, negative means west, and
positive means east. Using this approach, you would enter41.714775, -72.727260for ARRL headquarters, and the London
example is51.50471, -0.26781. " -
Please enter simply
0, 26
for location. Then it works.
Thank you so much !! I was putting it in as "0°N 26°E"
I am available as a "website test crasher".... Very reasonable rates
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Easy when you know how! Thanks for that... (I don't even know what KML is... (yet!))
Ok, I now know what KML is! Thank you for teaching me something new today!
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Ok, I now know what KML is! Thank you for teaching me something new today!
Sorry.... it is Keyhole Markup Language, similar to XML and used for doing clever stuff in google earth etc. I use it in a simple way to overlay images or tracks on maps. This is rather useful if you have been doing mobile coverage measurements or want to overlay a prediction on top of a map.
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First I draw the theoretical footprint of the sat based on the position and distance from the earth. Then I generated the DXCC list.
See files attached.
Nice DXCC List. Seems that OX (North America) is issing in the list, which has a low elevation access to QO-100 from some of the villages on the East Coast. Otherwise a nice complete list.
73, Oscar
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Sorry.... it is Keyhole Markup Language, similar to XML and used for doing clever stuff in google earth etc. I use it in a simple way to overlay images or tracks on maps. This is rather useful if you have been doing mobile coverage measurements or want to overlay a prediction on top of a map.
That's ok. I looked it up on Wikipedia.... Could you see your way open to sending me a sample/simple KML file so I can see what the content looks like?
73's David
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Nice DXCC List. Seems that OX (North America) is issing in the list, which has a low elevation access to QO-100 from some of the villages on the East Coast. Otherwise a nice complete list.
73, Oscar
Hi Oscar
Well spotted. My mistake. Here is the explanation. I started with the full latest DXCC list. Then I sorted by continents, and after I deleted the entities that were not covered by QO-100 theoretical footprint. I guess I thought it was safe to delete all NA, but my assumption was wrong.
Thank you for pointing that. Revised list attached.
Good Dx
73 FCosta, CT1EAT/M0HOJ
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September 2019 - April 2020
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Satellite Distance Records
AMSAT-NA keeps a list of Satellite Distance Records:
https://www.amsat.org/satellite-distance-records/
Please email n8hm@amsat.org if you wish to claim a new record, longer distance QSO not yet documented, or records for any other satellite/transponder not yet listed.
I haven't yet seen an entry for QO-100, so who will be first?
Good Luck!
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From North on Svalbard JW to South to DP0GVN ?
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Why would AMSAT NA have such a competition? Surely all QSOs via geo are more or less the same distance? Earth-satellite-earth. OK with a few 1000km difference on the footprint edges. Measuring the great circle distance is irrelevant as its not taking that route. What might make sense is the QSO closest to the geometric limits.
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Yes, correct is the range of our signals via satellite. It's easier to look on QRZ.COM and copy the landline distance. But it's a funny "pseudo competition".
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Yes, correct is the range of our signals via satellite. It's easier to look on QRZ.COM and copy the landline distance. But it's a funny "pseudo competition".
I think it's worse than that as it implies we are ignorant of the real path the signal is taking, like claiming DX when working that DX through your local internet connected repeater. That's not the case for anyone working through QO100 as they will know very well the path because they first had the difficult task to set up the necessary equipment.
What is challenging here is geometry. That could be a basis for competitive DX distance like records, How low on the horizon can you still access the transponder, or perhaps I should say how far below the horizon as that should be possible too, though not by much, due to refraction. 9V1HY to PR8ZX is very low elevation at both ends, but so would be Greenland to Svalbard even though great circle it's not so far. Iceland to Antarctica would be more moderate DX, with 10 degree elevation but its a very long way by boat. For those of us with relatively high elevations it's who we can work with their lowest elevation, but they are doing practically all the work. At HF, DX often means rarity rather than distance. Who has worked the most countries.
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I think it's worse than that as it implies we are ignorant of the real path the signal is taking, like claiming DX when working that DX through your local internet connected repeater. That's not the case for anyone working through QO100 as they will know very well the path because they first had the difficult task to set up the necessary equipment.
Agreed, but I don't see it that closely. For such a "competition" we need a common denominator and I think nobody is ignorant here. It should make fun.
What is challenging here is geometry. That could be a basis for competitive DX distance like records, How low on the horizon can you still access the transponder, or perhaps I should say how far below the horizon as that should be possible too, though not by much, due to refraction. 9V1HY to PR8ZX is very low elevation at both ends, but so would be Greenland to Svalbard even though great circle it's not so far. Iceland to Antarctica would be more moderate DX, with 10 degree elevation but its a very long way by boat. For those of us with relatively high elevations it's who we can work with their lowest elevation, but they are doing practically all the work. At HF, DX often means rarity rather than distance. Who has worked the most countries.
Also agreed, you are free to initiate such a real competition. My suggestion is to calculate the range to the sat and to add the distances between the two DX-stations. My calculated range to QO-100 are 38'311 km based on actual Kepler-elements. This to calculate is easy with a GEO-sat but not with a LEO-sat. So it's easier to calculate with the landline distances for all satellites.
Have fun and stay save
